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Question

Posted on: February 20 2019

Prepare calcium lactatropic syrup for a child of 1 year according to the specified composition do not succeed.

R/lactic acid 27g; CaCO3 15g; Orange peel syrup 40g; AQUA 100ML; Raspberry Syrup AD 200ml. 2 x per day 10 ml After telephone contact with the pediatrician we had to omit the orange peel syrup as strong orange peel tincture (contains alcohol) is used for the preparation of this syrup. . But we suspect that this tincture still has a function in the stability of the preparation, because after making without this tincture we obtain a hard lump.

Answer

If we make the calculation according to the equation that 1 mol   (90 g) lactic acid reacts with 1 mol of calcium carbonate (100 g) for the formation of 1 mol Ca lactate (218 g) then gives 15 g CaCO3 32.7 G Ca lactate.    

Water solubility of Ca lactate = 48 g/L   or 9.6 g/200 ml.

If we assume, that due to the large dose of Ca lactate, the amounts of lactic acid and CaCO3 are for 1 L then per 200 ml the amount of     CaCO3 = 3 g   and the amount of lactic acid 2.7 g.   This gives 6.54 G Ca lactate per 200 ML, a quantity lower than the maximum solubility.

A similar syrup "the phospfolacate syrup PB V" contains 5 g of calcium lactate per 200 g syrup (= 150 ml).  

An unknown remains the influence of the nature of the raspberry syrup used. One can choose this preparation between   raspberry liquid extract, or raspberry aroma Fantaisie or use of raspberries syrup fantaisie or of course. One cannot exclude that all these different raw materials give the same pH to the finished product??